2c(9-5c)+6(c^2-c)=0

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Solution for 2c(9-5c)+6(c^2-c)=0 equation:


Simplifying
2c(9 + -5c) + 6(c2 + -1c) = 0
(9 * 2c + -5c * 2c) + 6(c2 + -1c) = 0
(18c + -10c2) + 6(c2 + -1c) = 0

Reorder the terms:
18c + -10c2 + 6(-1c + c2) = 0
18c + -10c2 + (-1c * 6 + c2 * 6) = 0
18c + -10c2 + (-6c + 6c2) = 0

Reorder the terms:
18c + -6c + -10c2 + 6c2 = 0

Combine like terms: 18c + -6c = 12c
12c + -10c2 + 6c2 = 0

Combine like terms: -10c2 + 6c2 = -4c2
12c + -4c2 = 0

Solving
12c + -4c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '4c'.
4c(3 + -1c) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3

Solution

c = {0, 3}

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